Integrand size = 16, antiderivative size = 51 \[ \int \frac {1}{x^4 \left (a+b \log \left (c x^n\right )\right )} \, dx=\frac {e^{\frac {3 a}{b n}} \left (c x^n\right )^{3/n} \operatorname {ExpIntegralEi}\left (-\frac {3 \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{b n x^3} \]
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Time = 0.03 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {2347, 2209} \[ \int \frac {1}{x^4 \left (a+b \log \left (c x^n\right )\right )} \, dx=\frac {e^{\frac {3 a}{b n}} \left (c x^n\right )^{3/n} \operatorname {ExpIntegralEi}\left (-\frac {3 \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{b n x^3} \]
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Rule 2209
Rule 2347
Rubi steps \begin{align*} \text {integral}& = \frac {\left (c x^n\right )^{3/n} \text {Subst}\left (\int \frac {e^{-\frac {3 x}{n}}}{a+b x} \, dx,x,\log \left (c x^n\right )\right )}{n x^3} \\ & = \frac {e^{\frac {3 a}{b n}} \left (c x^n\right )^{3/n} \text {Ei}\left (-\frac {3 \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{b n x^3} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.00 \[ \int \frac {1}{x^4 \left (a+b \log \left (c x^n\right )\right )} \, dx=\frac {e^{\frac {3 a}{b n}} \left (c x^n\right )^{3/n} \operatorname {ExpIntegralEi}\left (-\frac {3 \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{b n x^3} \]
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.46 (sec) , antiderivative size = 242, normalized size of antiderivative = 4.75
method | result | size |
risch | \(-\frac {c^{\frac {3}{n}} \left (x^{n}\right )^{\frac {3}{n}} {\mathrm e}^{\frac {-\frac {3 i b \pi \,\operatorname {csgn}\left (i c \right ) \operatorname {csgn}\left (i x^{n}\right ) \operatorname {csgn}\left (i c \,x^{n}\right )}{2}+\frac {3 i b \pi \,\operatorname {csgn}\left (i c \right ) \operatorname {csgn}\left (i c \,x^{n}\right )^{2}}{2}+\frac {3 i b \pi \,\operatorname {csgn}\left (i x^{n}\right ) \operatorname {csgn}\left (i c \,x^{n}\right )^{2}}{2}-\frac {3 i b \pi \operatorname {csgn}\left (i c \,x^{n}\right )^{3}}{2}+3 a}{b n}} \operatorname {Ei}_{1}\left (3 \ln \left (x \right )+\frac {-\frac {3 i b \pi \,\operatorname {csgn}\left (i c \right ) \operatorname {csgn}\left (i x^{n}\right ) \operatorname {csgn}\left (i c \,x^{n}\right )}{2}+\frac {3 i b \pi \,\operatorname {csgn}\left (i c \right ) \operatorname {csgn}\left (i c \,x^{n}\right )^{2}}{2}+\frac {3 i b \pi \,\operatorname {csgn}\left (i x^{n}\right ) \operatorname {csgn}\left (i c \,x^{n}\right )^{2}}{2}-\frac {3 i b \pi \operatorname {csgn}\left (i c \,x^{n}\right )^{3}}{2}+3 b \ln \left (c \right )+3 b \left (\ln \left (x^{n}\right )-n \ln \left (x \right )\right )+3 a}{b n}\right )}{b n \,x^{3}}\) | \(242\) |
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Time = 0.29 (sec) , antiderivative size = 42, normalized size of antiderivative = 0.82 \[ \int \frac {1}{x^4 \left (a+b \log \left (c x^n\right )\right )} \, dx=\frac {e^{\left (\frac {3 \, {\left (b \log \left (c\right ) + a\right )}}{b n}\right )} \operatorname {log\_integral}\left (\frac {e^{\left (-\frac {3 \, {\left (b \log \left (c\right ) + a\right )}}{b n}\right )}}{x^{3}}\right )}{b n} \]
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\[ \int \frac {1}{x^4 \left (a+b \log \left (c x^n\right )\right )} \, dx=\int \frac {1}{x^{4} \left (a + b \log {\left (c x^{n} \right )}\right )}\, dx \]
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\[ \int \frac {1}{x^4 \left (a+b \log \left (c x^n\right )\right )} \, dx=\int { \frac {1}{{\left (b \log \left (c x^{n}\right ) + a\right )} x^{4}} \,d x } \]
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\[ \int \frac {1}{x^4 \left (a+b \log \left (c x^n\right )\right )} \, dx=\int { \frac {1}{{\left (b \log \left (c x^{n}\right ) + a\right )} x^{4}} \,d x } \]
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Timed out. \[ \int \frac {1}{x^4 \left (a+b \log \left (c x^n\right )\right )} \, dx=\int \frac {1}{x^4\,\left (a+b\,\ln \left (c\,x^n\right )\right )} \,d x \]
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